Kuis (medium-hard):
Diketahui persamaan-persamaan
[tex]\begin{aligned} \rm \lim _{x\to\infty}~\frac{\sqrt{3x^{10}}-x^3+\sqrt[4]{16x^8}}{\sqrt[3]{8x^{15}}+x-\sqrt{2x}} &~=~ \rm sin(\bf a\rm)~\left[0~~~\le\bf a\rm\le\frac{1}{2}~\pi\right] \\ \rm \lim _{x\to\infty}~\frac{\sqrt{6x^{12}}+\sqrt[3]{8x^9}-\sqrt[6]{8x^{36}}}{x^3-\sqrt[5]{32x^{10}}+\sqrt[4]{256x^{24}}} &~= ~\rm cos(\bf b\rm)~\left[\frac{3\pi }{2}\le\bf b\rm\le2\pi\right]\end{aligned}\\\\\\\displaystyle\sf Tentukan~nilai~\left(~\frac{a}{4b}~\right)^{~-1}[/tex]
(A.) = 9,5
(B.) = 5
(C.) = 2,5
(D.) = 19
(E.) = 4,75![]()
Diketahui persamaan-persamaan
[tex]\begin{aligned} \rm \lim _{x\to\infty}~\frac{\sqrt{3x^{10}}-x^3+\sqrt[4]{16x^8}}{\sqrt[3]{8x^{15}}+x-\sqrt{2x}} &~=~ \rm sin(\bf a\rm)~\left[0~~~\le\bf a\rm\le\frac{1}{2}~\pi\right] \\ \rm \lim _{x\to\infty}~\frac{\sqrt{6x^{12}}+\sqrt[3]{8x^9}-\sqrt[6]{8x^{36}}}{x^3-\sqrt[5]{32x^{10}}+\sqrt[4]{256x^{24}}} &~= ~\rm cos(\bf b\rm)~\left[\frac{3\pi }{2}\le\bf b\rm\le2\pi\right]\end{aligned}\\\\\\\displaystyle\sf Tentukan~nilai~\left(~\frac{a}{4b}~\right)^{~-1}[/tex]
(A.) = 9,5
(B.) = 5
(C.) = 2,5
(D.) = 19
(E.) = 4,75
Jawaban:
(D.) = 19
Penjelasan dengan langkah-langkah:
penjelasan ada di gambar.
[answer.2.content]
